1(6m+8)=4(17-m)

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Solution for 1(6m+8)=4(17-m) equation: 



1(6m+8)=4(17-m)

We move all terms to the left:

1(6m+8)-(4(17-m))=0

We add all the numbers together, and all the variables

1(6m+8)-(4(-1m+17))=0



We calculate terms in parentheses: -(4(-1m+17)), so:

4(-1m+17)

We multiply parentheses

-4m+68

Back to the equation:

-(-4m+68)



We get rid of parentheses

1(6m+8)+4m-68=0

We add all the numbers together, and all the variables

4m+1(6m+8)-68=0

We move all terms containing m to the left, all other terms to the right

4m+1(6m+8)=68

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