3=3(b+12)+6

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Solution for 3=3(b+12)+6 equation: 



3=3(b+12)+6

We move all terms to the left:

3-(3(b+12)+6)=0



We calculate terms in parentheses: -(3(b+12)+6), so:

3(b+12)+6

We multiply parentheses

3b+36+6

We add all the numbers together, and all the variables

3b+42

Back to the equation:

-(3b+42)



We get rid of parentheses

-3b-42+3=0

We add all the numbers together, and all the variables

-3b-39=0

We move all terms containing b to the left, all other terms to the right

-3b=39

b=39/-3

b=-13

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