1(33)+4x=3(x+33)

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Solution for 1(33)+4x=3(x+33) equation: 



1(33)+4x=3(x+33)

We move all terms to the left:

1(33)+4x-(3(x+33))=0



We calculate terms in parentheses: -(3(x+33)), so:

3(x+33)

We multiply parentheses

3x+99

Back to the equation:

-(3x+99)



We get rid of parentheses

4x-3x-99+133=0

We add all the numbers together, and all the variables

x+34=0

We move all terms containing x to the left, all other terms to the right

x=-34

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