1(33)+4x=4(x+33)

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Solution for 1(33)+4x=4(x+33) equation: 



1(33)+4x=4(x+33)

We move all terms to the left:

1(33)+4x-(4(x+33))=0



We calculate terms in parentheses: -(4(x+33)), so:

4(x+33)

We multiply parentheses

4x+132

Back to the equation:

-(4x+132)



We get rid of parentheses

4x-4x-132+133=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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