1(16a-4a)=4(2a+12)

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Solution for 1(16a-4a)=4(2a+12) equation: 



1(16a-4a)=4(2a+12)

We move all terms to the left:

1(16a-4a)-(4(2a+12))=0

We add all the numbers together, and all the variables

1(+12a)-(4(2a+12))=0



We calculate terms in parentheses: -(4(2a+12)), so:

4(2a+12)

We multiply parentheses

8a+48

Back to the equation:

-(8a+48)



We get rid of parentheses

1(+12a)-8a-48=0

We add all the numbers together, and all the variables

-8a+1(+12a)-48=0

We move all terms containing a to the left, all other terms to the right

-8a+1(+12a)=48

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