(3x-3)(2x)=112

Solution for (3x-3)(2x)=112 equation:

(3x-3)(2x)=112

We move all terms to the left:

(3x-3)(2x)-(112)=0

We multiply parentheses

6x^2-6x-112=0

a = 6; b = -6; c = -112;
Δ = b2-4ac
Δ = -62-4·6·(-112)
Δ = 2724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2724}=\sqrt{4*681}=\sqrt{4}*\sqrt{681}=2\sqrt{681}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{681}}{2*6}=\frac{6-2\sqrt{681}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{681}}{2*6}=\frac{6+2\sqrt{681}}{12}
$