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0=x(10x-7)-23
We move all terms to the left:
0-(x(10x-7)-23)=0
We add all the numbers together, and all the variables
-(x(10x-7)-23)=0
We calculate terms in parentheses: -(x(10x-7)-23), so:We get rid of parentheses
x(10x-7)-23
We multiply parentheses
10x^2-7x-23
Back to the equation:
-(10x^2-7x-23)
-10x^2+7x+23=0
a = -10; b = 7; c = +23;
Δ = b2-4ac
Δ = 72-4·(-10)·23
Δ = 969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{969}}{2*-10}=\frac{-7-\sqrt{969}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{969}}{2*-10}=\frac{-7+\sqrt{969}}{-20} $
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