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x=(-3/5)x+6
We move all terms to the left:
x-((-3/5)x+6)=0
Domain of the equation: 5)x+6)!=0We multiply all the terms by the denominator
x!=0/1
x!=0
x∈R
x*5)x+6)-((-3=0
Wy multiply elements
5x^2-3=0
a = 5; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·5·(-3)
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{15}}{2*5}=\frac{0-2\sqrt{15}}{10} =-\frac{2\sqrt{15}}{10} =-\frac{\sqrt{15}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{15}}{2*5}=\frac{0+2\sqrt{15}}{10} =\frac{2\sqrt{15}}{10} =\frac{\sqrt{15}}{5} $
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