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0=x(6x+19)-60
We move all terms to the left:
0-(x(6x+19)-60)=0
We add all the numbers together, and all the variables
-(x(6x+19)-60)=0
We calculate terms in parentheses: -(x(6x+19)-60), so:We get rid of parentheses
x(6x+19)-60
We multiply parentheses
6x^2+19x-60
Back to the equation:
-(6x^2+19x-60)
-6x^2-19x+60=0
a = -6; b = -19; c = +60;
Δ = b2-4ac
Δ = -192-4·(-6)·60
Δ = 1801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{1801}}{2*-6}=\frac{19-\sqrt{1801}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{1801}}{2*-6}=\frac{19+\sqrt{1801}}{-12} $
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