4z+(z+10)=(z+50)

Solution for 4z+(z+10)=(z+50) equation:

4z+(z+10)=(z+50)

We move all terms to the left:

4z+(z+10)-((z+50))=0

We get rid of parentheses

4z+z-((z+50))+10=0


We calculate terms in parentheses: -((z+50)), so:

(z+50)

We get rid of parentheses

z+50

Back to the equation:

-(z+50)


We add all the numbers together, and all the variables

5z-(z+50)+10=0

We get rid of parentheses

5z-z-50+10=0

We add all the numbers together, and all the variables

4z-40=0

We move all terms containing z to the left, all other terms to the right

4z=40

z=40/4

z=10