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0=x(1.296-0.00036x)
We move all terms to the left:
0-(x(1.296-0.00036x))=0
We add all the numbers together, and all the variables
-(x(-0.00036x+1.296))+0=0
We add all the numbers together, and all the variables
-(x(-0.00036x+1.296))=0
We calculate terms in parentheses: -(x(-0.00036x+1.296)), so:We get rid of parentheses
x(-0.00036x+1.296)
We multiply parentheses
0x^2+1.296x
We add all the numbers together, and all the variables
x^2+1.296x
Back to the equation:
-(x^2+1.296x)
-x^2-1.296x=0
We add all the numbers together, and all the variables
-1x^2-1.296x=0
a = -1; b = -1.296; c = 0;
Δ = b2-4ac
Δ = -1.2962-4·(-1)·0
Δ = 1.679616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.296)-\sqrt{1.679616}}{2*-1}=\frac{1.296-\sqrt{1.679616}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.296)+\sqrt{1.679616}}{2*-1}=\frac{1.296+\sqrt{1.679616}}{-2} $
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