(3/2)y+3=2y+(1/2)

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Solution for (3/2)y+3=2y+(1/2) equation:



(3/2)y+3=2y+(1/2)
We move all terms to the left:
(3/2)y+3-(2y+(1/2))=0
Domain of the equation: 2)y!=0
y!=0/1
y!=0
y∈R
We add all the numbers together, and all the variables
(+3/2)y-(2y+(+1/2))+3=0
We multiply parentheses
3y^2-(2y+(+1/2))+3=0
We multiply all the terms by the denominator
3y^2*2))-(2y+(+1+3*2))=0
We add all the numbers together, and all the variables
3y^2*2))-(2y+7)=0
Wy multiply elements
6y^3=0
We do not support eypression: y^3

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