0=w(36-2w)

Solution for 0=w(36-2w) equation:

0=w(36-2w)

We move all terms to the left:

0-(w(36-2w))=0

We add all the numbers together, and all the variables

-(w(-2w+36))+0=0

We add all the numbers together, and all the variables

-(w(-2w+36))=0


We calculate terms in parentheses: -(w(-2w+36)), so:

w(-2w+36)

We multiply parentheses

-2w^2+36w

Back to the equation:

-(-2w^2+36w)


We get rid of parentheses

2w^2-36w=0

a = 2; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·2·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*2}=\frac{0}{4}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*2}=\frac{72}{4}
=18
$