2(6x-8)=40+40x

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Solution for 2(6x-8)=40+40x equation:



2(6x-8)=40+40x
We move all terms to the left:
2(6x-8)-(40+40x)=0
We add all the numbers together, and all the variables
2(6x-8)-(40x+40)=0
We multiply parentheses
12x-(40x+40)-16=0
We get rid of parentheses
12x-40x-40-16=0
We add all the numbers together, and all the variables
-28x-56=0
We move all terms containing x to the left, all other terms to the right
-28x=56
x=56/-28
x=-2

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