0=760x(1-9x)

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Solution for 0=760x(1-9x) equation:



0=760x(1-9x)
We move all terms to the left:
0-(760x(1-9x))=0
We add all the numbers together, and all the variables
-(760x(-9x+1))+0=0
We add all the numbers together, and all the variables
-(760x(-9x+1))=0
We calculate terms in parentheses: -(760x(-9x+1)), so:
760x(-9x+1)
We multiply parentheses
-6840x^2+760x
Back to the equation:
-(-6840x^2+760x)
We get rid of parentheses
6840x^2-760x=0
a = 6840; b = -760; c = 0;
Δ = b2-4ac
Δ = -7602-4·6840·0
Δ = 577600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{577600}=760$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-760)-760}{2*6840}=\frac{0}{13680} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-760)+760}{2*6840}=\frac{1520}{13680} =1/9 $

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