0=6t+3(2+9t)+7

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Solution for 0=6t+3(2+9t)+7 equation: 



0=6t+3(2+9t)+7

We move all terms to the left:

0-(6t+3(2+9t)+7)=0

We add all the numbers together, and all the variables

-(6t+3(9t+2)+7)+0=0

We add all the numbers together, and all the variables

-(6t+3(9t+2)+7)=0



We calculate terms in parentheses: -(6t+3(9t+2)+7), so:

6t+3(9t+2)+7

We multiply parentheses

6t+27t+6+7

We add all the numbers together, and all the variables

33t+13

Back to the equation:

-(33t+13)



We get rid of parentheses

-33t-13=0

We move all terms containing t to the left, all other terms to the right

-33t=13

t=13/-33

t=-13/33

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