(9/10)b-3=-(19/20)b+2

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Solution for (9/10)b-3=-(19/20)b+2 equation:



(9/10)b-3=-(19/20)b+2
We move all terms to the left:
(9/10)b-3-(-(19/20)b+2)=0
Domain of the equation: 10)b!=0
b!=0/1
b!=0
b∈R
Domain of the equation: 20)b+2)!=0
b!=0/1
b!=0
b∈R
We add all the numbers together, and all the variables
(+9/10)b-(-(+19/20)b+2)-3=0
We multiply parentheses
9b^2-(-(+19/20)b+2)-3=0
We multiply all the terms by the denominator
9b^2*20)b+2)-(-(-3*20)b+2)+19=0
We add all the numbers together, and all the variables
9b^2*20)b+2)-(-(-60)b+2)+19=0
Wy multiply elements
180b^3-60)b+2)+19=0
We do not support ebpression: b^3

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