0=48x+8x2

Solution for 0=48x+8x2 equation:

0=48x+8x^2

We move all terms to the left:

0-(48x+8x^2)=0

We add all the numbers together, and all the variables

-(48x+8x^2)=0

We get rid of parentheses

-8x^2-48x=0

a = -8; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·(-8)·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*-8}=\frac{0}{-16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*-8}=\frac{96}{-16}
=-6
$