-2(1y-4)=20-2y-12

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Solution for -2(1y-4)=20-2y-12 equation: 



-2(1y-4)=20-2y-12

We move all terms to the left:

-2(1y-4)-(20-2y-12)=0

We add all the numbers together, and all the variables

-2(y-4)-(-2y+8)=0

We multiply parentheses

-2y-(-2y+8)+8=0

We get rid of parentheses

-2y+2y-8+8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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