0=3(b+2)-3

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Solution for 0=3(b+2)-3 equation: 



0=3(b+2)-3

We move all terms to the left:

0-(3(b+2)-3)=0

We add all the numbers together, and all the variables

-(3(b+2)-3)=0



We calculate terms in parentheses: -(3(b+2)-3), so:

3(b+2)-3

We multiply parentheses

3b+6-3

We add all the numbers together, and all the variables

3b+3

Back to the equation:

-(3b+3)



We get rid of parentheses

-3b-3=0

We move all terms containing b to the left, all other terms to the right

-3b=3

b=3/-3

b=-1

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