2(u+3)=-2(4u-1)+4u

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Solution for 2(u+3)=-2(4u-1)+4u equation: 



2(u+3)=-2(4u-1)+4u

We move all terms to the left:

2(u+3)-(-2(4u-1)+4u)=0

We multiply parentheses

2u-(-2(4u-1)+4u)+6=0



We calculate terms in parentheses: -(-2(4u-1)+4u), so:

-2(4u-1)+4u

We add all the numbers together, and all the variables

4u-2(4u-1)

We multiply parentheses

4u-8u+2

We add all the numbers together, and all the variables

-4u+2

Back to the equation:

-(-4u+2)



We get rid of parentheses

2u+4u-2+6=0

We add all the numbers together, and all the variables

6u+4=0

We move all terms containing u to the left, all other terms to the right

6u=-4

u=-4/6

u=-2/3

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