0=2(y-3)+-4

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Solution for 0=2(y-3)+-4 equation: 



0=2(y-3)+-4

We move all terms to the left:

0-(2(y-3)+-4)=0

We add all the numbers together, and all the variables

-(2(y-3)+-4)=0

We use the square of the difference formula

-(2(y-3)-4)=0



We calculate terms in parentheses: -(2(y-3)-4), so:

2(y-3)-4

We multiply parentheses

2y-6-4

We add all the numbers together, and all the variables

2y-10

Back to the equation:

-(2y-10)



We get rid of parentheses

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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