4x-3(2-3x)=4(x-3)-39

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Solution for 4x-3(2-3x)=4(x-3)-39 equation:



4x-3(2-3x)=4(x-3)-39
We move all terms to the left:
4x-3(2-3x)-(4(x-3)-39)=0
We add all the numbers together, and all the variables
4x-3(-3x+2)-(4(x-3)-39)=0
We multiply parentheses
4x+9x-(4(x-3)-39)-6=0
We calculate terms in parentheses: -(4(x-3)-39), so:
4(x-3)-39
We multiply parentheses
4x-12-39
We add all the numbers together, and all the variables
4x-51
Back to the equation:
-(4x-51)
We add all the numbers together, and all the variables
13x-(4x-51)-6=0
We get rid of parentheses
13x-4x+51-6=0
We add all the numbers together, and all the variables
9x+45=0
We move all terms containing x to the left, all other terms to the right
9x=-45
x=-45/9
x=-5

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