0=-16t2+64t+82.8

Solution for 0=-16t2+64t+82.8 equation:

0=-16t^2+64t+82.8

We move all terms to the left:

0-(-16t^2+64t+82.8)=0

We add all the numbers together, and all the variables

-(-16t^2+64t+82.8)=0

We get rid of parentheses

16t^2-64t-82.8=0

a = 16; b = -64; c = -82.8;
Δ = b2-4ac
Δ = -642-4·16·(-82.8)
Δ = 9395.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-\sqrt{9395.2}}{2*16}=\frac{64-\sqrt{9395.2}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+\sqrt{9395.2}}{2*16}=\frac{64+\sqrt{9395.2}}{32}
$