-3(2y+4)-6=-4(y+5)+y

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Solution for -3(2y+4)-6=-4(y+5)+y equation: 



-3(2y+4)-6=-4(y+5)+y

We move all terms to the left:

-3(2y+4)-6-(-4(y+5)+y)=0

We multiply parentheses

-6y-(-4(y+5)+y)-12-6=0



We calculate terms in parentheses: -(-4(y+5)+y), so:

-4(y+5)+y

We add all the numbers together, and all the variables

y-4(y+5)

We multiply parentheses

y-4y-20

We add all the numbers together, and all the variables

-3y-20

Back to the equation:

-(-3y-20)



We add all the numbers together, and all the variables

-6y-(-3y-20)-18=0

We get rid of parentheses

-6y+3y+20-18=0

We add all the numbers together, and all the variables

-3y+2=0

We move all terms containing y to the left, all other terms to the right

-3y=-2

y=-2/-3

y=2/3

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