8-2(3y-5)+9y=7(y-2)

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Solution for 8-2(3y-5)+9y=7(y-2) equation: 



8-2(3y-5)+9y=7(y-2)

We move all terms to the left:

8-2(3y-5)+9y-(7(y-2))=0

We add all the numbers together, and all the variables

9y-2(3y-5)-(7(y-2))+8=0

We multiply parentheses

9y-6y-(7(y-2))+10+8=0



We calculate terms in parentheses: -(7(y-2)), so:

7(y-2)

We multiply parentheses

7y-14

Back to the equation:

-(7y-14)



We add all the numbers together, and all the variables

3y-(7y-14)+18=0

We get rid of parentheses

3y-7y+14+18=0

We add all the numbers together, and all the variables

-4y+32=0

We move all terms containing y to the left, all other terms to the right

-4y=-32

y=-32/-4

y=+8

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