0=-12x(x+3)

Solution for 0=-12x(x+3) equation:

0=-12x(x+3)

We move all terms to the left:

0-(-12x(x+3))=0

We add all the numbers together, and all the variables

-(-12x(x+3))=0


We calculate terms in parentheses: -(-12x(x+3)), so:

-12x(x+3)

We multiply parentheses

-12x^2-36x

Back to the equation:

-(-12x^2-36x)


We get rid of parentheses

12x^2+36x=0

a = 12; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·12·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*12}=\frac{-72}{24}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*12}=\frac{0}{24}
=0
$