11r-3(r+2)=3(4r-5)-7

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Solution for 11r-3(r+2)=3(4r-5)-7 equation: 



11r-3(r+2)=3(4r-5)-7

We move all terms to the left:

11r-3(r+2)-(3(4r-5)-7)=0

We multiply parentheses

11r-3r-(3(4r-5)-7)-6=0



We calculate terms in parentheses: -(3(4r-5)-7), so:

3(4r-5)-7

We multiply parentheses

12r-15-7

We add all the numbers together, and all the variables

12r-22

Back to the equation:

-(12r-22)



We add all the numbers together, and all the variables

8r-(12r-22)-6=0

We get rid of parentheses

8r-12r+22-6=0

We add all the numbers together, and all the variables

-4r+16=0

We move all terms containing r to the left, all other terms to the right

-4r=-16

r=-16/-4

r=+4

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