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0=(x+6)(x+0)
We move all terms to the left:
0-((x+6)(x+0))=0
We add all the numbers together, and all the variables
-((x+6)(+x))+0=0
We add all the numbers together, and all the variables
-((x+6)(+x))=0
We multiply parentheses ..
-((+x^2+6x))=0
We calculate terms in parentheses: -((+x^2+6x)), so:We get rid of parentheses
(+x^2+6x)
We get rid of parentheses
x^2+6x
Back to the equation:
-(x^2+6x)
-x^2-6x=0
We add all the numbers together, and all the variables
-1x^2-6x=0
a = -1; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-1)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-1}=\frac{0}{-2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-1}=\frac{12}{-2} =-6 $
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