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484=x(x+33)
We move all terms to the left:
484-(x(x+33))=0
We calculate terms in parentheses: -(x(x+33)), so:We get rid of parentheses
x(x+33)
We multiply parentheses
x^2+33x
Back to the equation:
-(x^2+33x)
-x^2-33x+484=0
We add all the numbers together, and all the variables
-1x^2-33x+484=0
a = -1; b = -33; c = +484;
Δ = b2-4ac
Δ = -332-4·(-1)·484
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-55}{2*-1}=\frac{-22}{-2} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+55}{2*-1}=\frac{88}{-2} =-44 $
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