0=(5-7i)/(2-5i)

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Solution for 0=(5-7i)/(2-5i) equation: 


D( i )

2-(5*i) = 0

2-(5*i) = 0

2-(5*i) = 0

2-5*i = 0

2-5*i = 0 // - 2

-5*i = -2 // : -5

i = -2/(-5)

i = 2/5

i in (-oo:2/5) U (2/5:+oo)

0 = (5-(7*i))/(2-(5*i)) // - (5-(7*i))/(2-(5*i))

0-((5-(7*i))/(2-(5*i))) = 0

-((5-7*i)/(2-5*i)) = 0

(-1*(5-7*i))/(2-5*i) = 0

( -1 )

-1 = 0

i belongs to the empty set

( 5-7*i )

5-7*i = 0 // - 5

-7*i = -5 // : -7

i = -5/(-7)

i = 5/7

i = 5/7

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