(2x-3)/(x-4)=(7/5)

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Solution for (2x-3)/(x-4)=(7/5) equation: 


D( x )

x-4 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

(2*x-3)/(x-4) = 7/5 // - 7/5

(2*x-3)/(x-4)-(7/5) = 0

(2*x-3)/(x-4)-7/5 = 0

(5*(2*x-3))/(5*(x-4))+(-7*(x-4))/(5*(x-4)) = 0

5*(2*x-3)-7*(x-4) = 0

3*x+13 = 0

(3*x+13)/(5*(x-4)) = 0

(3*x+13)/(5*(x-4)) = 0 // * 5*(x-4)

3*x+13 = 0

3*x+13 = 0 // - 13

3*x = -13 // : 3

x = -13/3

x = -13/3

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