0=(-x+1)(-3x+4)

Solution for 0=(-x+1)(-3x+4) equation:

0=(-x+1)(-3x+4)

We move all terms to the left:

0-((-x+1)(-3x+4))=0

We add all the numbers together, and all the variables

-((-1x+1)(-3x+4))+0=0

We add all the numbers together, and all the variables

-((-1x+1)(-3x+4))=0

We multiply parentheses ..

-((+3x^2-4x-3x+4))=0


We calculate terms in parentheses: -((+3x^2-4x-3x+4)), so:

(+3x^2-4x-3x+4)

We get rid of parentheses

3x^2-4x-3x+4

We add all the numbers together, and all the variables

3x^2-7x+4

Back to the equation:

-(3x^2-7x+4)


We get rid of parentheses

-3x^2+7x-4=0

a = -3; b = 7; c = -4;
Δ = b2-4ac
Δ = 72-4·(-3)·(-4)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1}{2*-3}=\frac{-8}{-6}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1}{2*-3}=\frac{-6}{-6}
=1
$