0=(-10+3x)*x

Solution for 0=(-10+3x)*x equation:

0=(-10+3x)*x

We move all terms to the left:

0-((-10+3x)*x)=0

We add all the numbers together, and all the variables

-((3x-10)*x)+0=0

We add all the numbers together, and all the variables

-((3x-10)*x)=0


We calculate terms in parentheses: -((3x-10)*x), so:

(3x-10)*x

We multiply parentheses

3x^2-10x

Back to the equation:

-(3x^2-10x)


We get rid of parentheses

-3x^2+10x=0

a = -3; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-3)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-3}=\frac{-20}{-6}
=3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-3}=\frac{0}{-6}
=0
$