12-((2x/3)+x)=2

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Solution for 12-((2x/3)+x)=2 equation: 



12-((2x/3)+x)=2

We move all terms to the left:

12-((2x/3)+x)-(2)=0



Domain of the equation: 3)+x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+2x/3)+x)+12-2=0

We add all the numbers together, and all the variables

-((+2x/3)+x)+10=0

We multiply all the terms by the denominator


-((+2x+10*3)+x)=0



We calculate terms in parentheses: -((+2x+10*3)+x), so:

(+2x+10*3)+x

We add all the numbers together, and all the variables

(2x+30)+x

We add all the numbers together, and all the variables

x+(2x+30)

We get rid of parentheses

x+2x+30

We add all the numbers together, and all the variables

3x+30

Back to the equation:

-(3x+30)



We get rid of parentheses

-3x-30=0

We move all terms containing x to the left, all other terms to the right

-3x=30

x=30/-3

x=-10

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