03/4(8x-12)=4x+9

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Solution for 03/4(8x-12)=4x+9 equation: 



03/4(8x-12)=4x+9

We move all terms to the left:

03/4(8x-12)-(4x+9)=0



Domain of the equation: 4(8x-12)!=0

x∈R



We get rid of parentheses

03/4(8x-12)-4x-9=0

We multiply all the terms by the denominator


-4x*4(8x-12)-9*4(8x-12)+03=0

We add all the numbers together, and all the variables

-4x*4(8x-12)-9*4(8x-12)+3=0

Wy multiply elements

-16x^2(8-36x(8+3=0

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