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2/5x+13=53
We move all terms to the left:
2/5x+13-(53)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2/5x-40=0
We multiply all the terms by the denominator
-40*5x+2=0
Wy multiply elements
-200x+2=0
We move all terms containing x to the left, all other terms to the right
-200x=-2
x=-2/-200
x=1/100
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