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0.75t^2-61t+550=0
a = 0.75; b = -61; c = +550;
Δ = b2-4ac
Δ = -612-4·0.75·550
Δ = 2071
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-\sqrt{2071}}{2*0.75}=\frac{61-\sqrt{2071}}{1.5} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+\sqrt{2071}}{2*0.75}=\frac{61+\sqrt{2071}}{1.5} $
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