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(3y+19)(8y+5)=0
We multiply parentheses ..
(+24y^2+15y+152y+95)=0
We get rid of parentheses
24y^2+15y+152y+95=0
We add all the numbers together, and all the variables
24y^2+167y+95=0
a = 24; b = 167; c = +95;
Δ = b2-4ac
Δ = 1672-4·24·95
Δ = 18769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{18769}=137$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(167)-137}{2*24}=\frac{-304}{48} =-6+1/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(167)+137}{2*24}=\frac{-30}{48} =-5/8 $
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