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0.72=x(2-x)
We move all terms to the left:
0.72-(x(2-x))=0
We add all the numbers together, and all the variables
-(x(-1x+2))+0.72=0
We calculate terms in parentheses: -(x(-1x+2)), so:We get rid of parentheses
x(-1x+2)
We multiply parentheses
-1x^2+2x
Back to the equation:
-(-1x^2+2x)
1x^2-2x+0.72=0
We add all the numbers together, and all the variables
x^2-2x+0.72=0
a = 1; b = -2; c = +0.72;
Δ = b2-4ac
Δ = -22-4·1·0.72
Δ = 1.12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{1.12}}{2*1}=\frac{2-\sqrt{1.12}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{1.12}}{2*1}=\frac{2+\sqrt{1.12}}{2} $
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