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0.7(x+7)(x-5)=0
We multiply parentheses ..
0.7(+x^2-5x+7x-35)=0
We multiply parentheses
0.7x^2-3.5x+4.9x-24.5=0
We add all the numbers together, and all the variables
0.7x^2+1.4x-24.5=0
a = 0.7; b = 1.4; c = -24.5;
Δ = b2-4ac
Δ = 1.42-4·0.7·(-24.5)
Δ = 70.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.4)-\sqrt{70.56}}{2*0.7}=\frac{-1.4-\sqrt{70.56}}{1.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.4)+\sqrt{70.56}}{2*0.7}=\frac{-1.4+\sqrt{70.56}}{1.4} $
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