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5q/(3-q)=2
We move all terms to the left:
5q/(3-q)-(2)=0
Domain of the equation: (3-q)!=0We add all the numbers together, and all the variables
We move all terms containing q to the left, all other terms to the right
-q!=-3
q!=-3/-1
q!=+3
q∈R
5q/(-1q+3)-2=0
We multiply all the terms by the denominator
5q-2*(-1q+3)=0
We multiply parentheses
5q+2q-6=0
We add all the numbers together, and all the variables
7q-6=0
We move all terms containing q to the left, all other terms to the right
7q=6
q=6/7
q=6/7
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