0.7(3x+2)=1.1-(x+5)

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Solution for 0.7(3x+2)=1.1-(x+5) equation: 



0.7(3x+2)=1.1-(x+5)

We move all terms to the left:

0.7(3x+2)-(1.1-(x+5))=0

We multiply parentheses

2.1x-(1.1-(x+5))+1.4=0



We calculate terms in parentheses: -(1.1-(x+5)), so:

1.1-(x+5)

determiningTheFunctionDomain
-(x+5)+1.1

We get rid of parentheses

-x-5+1.1

We add all the numbers together, and all the variables

-1x-3.9

Back to the equation:

-(-1x-3.9)



We get rid of parentheses

2.1x+1x+3.9+1.4=0

We add all the numbers together, and all the variables

3.1x+5.3=0

We move all terms containing x to the left, all other terms to the right

3.1x=-5.3

x=-5.3/3.1

x=-1+2.2/3.1

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