0.5y2-y=0

Solution for 0.5y2-y=0 equation:

0.5y^2-y=0

We add all the numbers together, and all the variables

0.5y^2-1y=0

a = 0.5; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·0.5·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*0.5}=\frac{0}{1}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*0.5}=\frac{2}{1}
=2
$