X2+4x-4800=0

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Solution for X2+4x-4800=0 equation:



X2+4X-4800=0
We add all the numbers together, and all the variables
X^2+4X-4800=0
a = 1; b = 4; c = -4800;
Δ = b2-4ac
Δ = 42-4·1·(-4800)
Δ = 19216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{19216}=\sqrt{16*1201}=\sqrt{16}*\sqrt{1201}=4\sqrt{1201}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{1201}}{2*1}=\frac{-4-4\sqrt{1201}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{1201}}{2*1}=\frac{-4+4\sqrt{1201}}{2} $

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