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0.5n+12n*1.5n=28
We move all terms to the left:
0.5n+12n*1.5n-(28)=0
Wy multiply elements
12n^2+0.5n-28=0
a = 12; b = 0.5; c = -28;
Δ = b2-4ac
Δ = 0.52-4·12·(-28)
Δ = 1344.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{1344.25}}{2*12}=\frac{-0.5-\sqrt{1344.25}}{24} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{1344.25}}{2*12}=\frac{-0.5+\sqrt{1344.25}}{24} $
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