3d(d+1)=5(3d-7)-2

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Solution for 3d(d+1)=5(3d-7)-2 equation: 



3d(d+1)=5(3d-7)-2

We move all terms to the left:

3d(d+1)-(5(3d-7)-2)=0

We multiply parentheses

3d^2+3d-(5(3d-7)-2)=0



We calculate terms in parentheses: -(5(3d-7)-2), so:

5(3d-7)-2

We multiply parentheses

15d-35-2

We add all the numbers together, and all the variables

15d-37

Back to the equation:

-(15d-37)



We get rid of parentheses

3d^2+3d-15d+37=0

We add all the numbers together, and all the variables

3d^2-12d+37=0

a = 3; b = -12; c = +37;
Δ = b2-4ac
Δ = -122-4·3·37
Δ = -300
Delta is less than zero, so there is no solution for the equation

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