0.5(x-2)=0.3(2x+1)-1.2

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Solution for 0.5(x-2)=0.3(2x+1)-1.2 equation: 



0.5(x-2)=0.3(2x+1)-1.2

We move all terms to the left:

0.5(x-2)-(0.3(2x+1)-1.2)=0

We multiply parentheses

0.5x-(0.3(2x+1)-1.2)-1=0



We calculate terms in parentheses: -(0.3(2x+1)-1.2), so:

0.3(2x+1)-1.2

We multiply parentheses

0.6x+0.3-1.2

We add all the numbers together, and all the variables

0.6x-0.9

Back to the equation:

-(0.6x-0.9)



We get rid of parentheses

0.5x-0.6x+0.9-1=0

We add all the numbers together, and all the variables

-0.1x-0.1=0

We move all terms containing x to the left, all other terms to the right

-0.1x=0.1

x=0.1/-0.1

x=-1

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