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0.5(6x-4)=3(x-2/3)
We move all terms to the left:
0.5(6x-4)-(3(x-2/3))=0
We add all the numbers together, and all the variables
0.5(6x-4)-(3(+x-2/3))=0
We multiply parentheses
3x-(3(+x-2/3))-2=0
We multiply all the terms by the denominator
3x*3))-(3(+x-2-2*3))=0
We add all the numbers together, and all the variables
3x*3))-(3(x-8))=0
We add all the numbers together, and all the variables
3x*3))-(3(x=0
Wy multiply elements
9x^2=0
a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{18}=0$
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