0.5(2+4x)=7(x-1)+2

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Solution for 0.5(2+4x)=7(x-1)+2 equation: 



0.5(2+4x)=7(x-1)+2

We move all terms to the left:

0.5(2+4x)-(7(x-1)+2)=0

We add all the numbers together, and all the variables

0.5(4x+2)-(7(x-1)+2)=0

We multiply parentheses

2x-(7(x-1)+2)+1=0



We calculate terms in parentheses: -(7(x-1)+2), so:

7(x-1)+2

We multiply parentheses

7x-7+2

We add all the numbers together, and all the variables

7x-5

Back to the equation:

-(7x-5)



We get rid of parentheses

2x-7x+5+1=0

We add all the numbers together, and all the variables

-5x+6=0

We move all terms containing x to the left, all other terms to the right

-5x=-6

x=-6/-5

x=1+1/5

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